Infrared Spectroscopy(IR)

1)  What is the principle of IR?
Infra-red spectroscopy is an important spectroscopy which gives almost complete information about the structure of a compound. The infra-red spectrum is containing a large number of absorption bands which provides much information about the molecule's structure. 

2)   What is the range of IR?

Region 
Wavelength range (λm)
Wave number range (cm-1) 
Near
0.78 - 2.5
12800 - 4000
Middle 
2.5 - 50
4000 - 200
Far 
50 - 1000 
200 - 10 

The absorption of infrared radiations can be expresses either in terms of wavelength or wave number. 
Wave length = 1/wave length (cm)

The intensity of bands observed in IR spectrum is expressed in terms of transmittance (T) or absorbance (A).

A = log10 (1/T)
Because of absorption of infra-red radiation, molecules become excited and move to lower to higher vibrational level. Each vibrational level is associated with a number of spaced rotational levels. Hence the absorption of infra-red caused to effect vibrational as well as rotational level and also called as vibrational- rotational spectra.
                                  

*Some common bands with their intensity values are as follows.

Typical Infrared Absorption Frequencies
Stretching Vibrations
Bending vibrations
Functional
class
Range
 (cm-1)
Intensity
Assignment
Range
(cm-1)
Intensity
Assignment
Alknes
2850-3000
strong
CH3, CH2 & CH
2 or 3 bands
1350-1470
1370-1390
720-725
Medium
Medium
Weak
CH2 & CH3 deformation
CH2 rocking
Alkenes
3020-3100
1630-1680
1900-2000
medium
strong
=C-H &
=CH2 (usually sharp)
C=C (symmetry reduces intensity)
C=C asymmetric stretch
880-995
780-850
675-730
Strong
Medium
Medium
+CH & =CH2
( out of plane bending)
cis-RCH=CHR
Alkynes
3300
2100-2250
Strong
CH (usually sharp)
C=C (Symmetry reduces intensity)
600-700
strong
C-H deformation
Arenes
3030
1600 &
1500

Medium-weak
C-H (may be several bands)
C=C (in ring)(2 bands)
(3 if conjugated)
690-900
Strong-medium
C-Hbending & ring puckering
Alcohols & phenols
3580-3650
3200-3550
970-1250

Strong
strong
O-H (free), usually sharp
O-H (H-bonded) usually broad C-O
1330-1430
650-770
medium
Var-weak
O-H bending (in plane)
O-H bend (out of palne)
Amines
3400-3500 (dil.solution)
3300-3400
(dil.solution)
1000-1250
Weak
weak
Medium
N-H (1o amines), 2 bands
N-H (2o amines) C-N
1550-1650
660-900
Medium-strong
Var
NH2 scissoring (1oamines) NH2 & NH wagging (shifts on H-bonding)
Aldehyde & ketones
2690-3840(2 bands)
1720-1740
1710-1720
Medium
strong
strong
strong
C-H (aldehyde C-H)
C=O (saturated ketone)
aryl ketone
Cyclo pentanone
cyclobutanone
1350-1360
1400-1450-1100
Strong
Strong
Medium
α-CH3 bending
α-CH2 bending
C-C-C bending
Carboxylic acids &derivatives
2500-3300(acids) overlap
C-H
1705-1720(acids)
1210-1320(acids)
1785-1815(acyl halides)
1750&1820 (anhydrides)
1040-1100
1735-1750(esters)
1000-1300
1630-1695(amides)
Strong
Strong
medium-Strong
Strong
Strong
Strong
Strong
Strong
Strong
O-H (very broad)
C=O (H-bonded)
O-C (Sometimes 2-peaks)
C=O
C=O (2-bands)
O-C
C=O
O-C(2-bands)
C=O(amide I band)
1395-1440
1590-1650
1500-1560
Medium
Medium
Medium
C-O-H bending
N-H (1oamide)
II band
N-H (2o amide)
II band
Nitriles
Isocyanates, Isothiocyanates, Diimides,
Azides &ketenes
2240-2260
2100-2270
Medium
Medium
C=N (sharp)
-N=C=O, -N=C=S
-N=C=N-, -N3
C=C=O



3) What are the applications of UV?

*Identification of functional group and structure elucidation
·      The identity of an organic compound can be established by using its finger print region (1400-1900 cm-1). 
·      The identity of an organic compound is confirmed of its finger print region exactly matches with the known spectrum of that compound. 
·      As compounds contain same functional group may have similar absorptions above 1500 cm-1 but they differ considerably in finger print region.
·      Each functional group absorbs a certain frequency of radiation and show corresponding peak. Hence the position of peak gives the information regarding the presence of certain functional group.
*Identification of structure of substances
·      Infra red spectroscopy is used to establish the structure of an unknown compound. 
·      All functional groups present in molecule absorbed at their characteristic wave number and the shift due to environment effect can be easily observed in spectrum. 
·      Form the data available, the whole structure of molecule can be predicated. 
·      If the IR spectrum of two compounds is exactly same, it shows that they are identical compounds. Hence must be samples of the same substances.
·      IR spectrum cannot identify the presence of Enantiomers as they show similar IR spectrum.
*Study of the progress of a chemical reaction 
·      Infra red spectroscopy is quite useful for studying the rate and progress of a chemical reaction. 
·      For example the reduction of ketone to secondary alcohol can be detected easily. As the absorption band of ketone is observed at about 1710 cm-1.
·      With the progress of reaction the band of >C=O group diminished and band of -O-H group at 3300 cm-1 appears. 
·      The progress of reaction can be determined by using the rate of disappearance of a certain absorption band of the reactant molecule and the rate of appearance of the absorption band of the product group. 
·      IR spectroscopy is also used to predict the products formed in photochemical reaction.
*Detection of impurities Infra-red
·      Infra red spectroscopy is also useful in the detection of the impurity in a compound by comparing its spectrum with the spectrum of the authentic sample of the compound.
·      A pure sample always consists of sharp peaks and bands while the impure sample will have poor bands with some additional bands.
*Quantitative analysis
·      The quantitative analysis of an organic mixture can be done by measuring the intensities of the absorption bands of each component and by knowing the optical density of the absorption bands for the pure substance. 

Comments